Base | Representation |
---|---|
bin | 110101101100100001… |
… | …0011000110010101001 |
3 | 102000122011220211202120 |
4 | 1223121002120302221 |
5 | 3342123432301101 |
6 | 124550050421453 |
7 | 11221333331514 |
oct | 1533102306251 |
9 | 360564824676 |
10 | 115310431401 |
11 | 449a28068a0 |
12 | 1a421291889 |
13 | ab487695c9 |
14 | 581c5b1d7b |
15 | 2eed41db36 |
hex | 1ad9098ca9 |
115310431401 has 64 divisors (see below), whose sum is σ = 183910300416. Its totient is φ = 63474278400.
The previous prime is 115310431319. The next prime is 115310431421. The reversal of 115310431401 is 104134013511.
It is not a de Polignac number, because 115310431401 - 215 = 115310398633 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (115310431421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1781925 + ... + 1845501.
It is an arithmetic number, because the mean of its divisors is an integer number (2873598444).
Almost surely, 2115310431401 is an apocalyptic number.
115310431401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
115310431401 is a deficient number, since it is larger than the sum of its proper divisors (68599869015).
115310431401 is a wasteful number, since it uses less digits than its factorization.
115310431401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63722.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 115310431401 its reverse (104134013511), we get a palindrome (219444444912).
The spelling of 115310431401 in words is "one hundred fifteen billion, three hundred ten million, four hundred thirty-one thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •