Base | Representation |
---|---|
bin | 10101011110101110… |
… | …10011010101011111 |
3 | 1002202200121010201121 |
4 | 22233113103111133 |
5 | 142104201242103 |
6 | 5144151551411 |
7 | 555526600144 |
oct | 125727232537 |
9 | 32680533647 |
10 | 11532055903 |
11 | 49885aa315 |
12 | 229a08b567 |
13 | 111a224424 |
14 | 7b580c3cb |
15 | 47763a6bd |
hex | 2af5d355f |
11532055903 has 2 divisors, whose sum is σ = 11532055904. Its totient is φ = 11532055902.
The previous prime is 11532055901. The next prime is 11532055943. The reversal of 11532055903 is 30955023511.
It is a weak prime.
It is an emirp because it is prime and its reverse (30955023511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11532055903 - 21 = 11532055901 is a prime.
Together with 11532055901, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11532055901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5766027951 + 5766027952.
It is an arithmetic number, because the mean of its divisors is an integer number (5766027952).
Almost surely, 211532055903 is an apocalyptic number.
11532055903 is a deficient number, since it is larger than the sum of its proper divisors (1).
11532055903 is an equidigital number, since it uses as much as digits as its factorization.
11532055903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20250, while the sum is 34.
The spelling of 11532055903 in words is "eleven billion, five hundred thirty-two million, fifty-five thousand, nine hundred three".
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