115325437 has 2 divisors, whose sum is σ = 115325438. Its totient is φ = 115325436.

The previous prime is 115325407. The next prime is 115325461. The reversal of 115325437 is 734523511.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81522841 + 33802596 = 9029^2 + 5814^2 .

It is a cyclic number.

It is not a de Polignac number, because 115325437 - 2¹⁵ = 115292669 is a prime.

It is a Chen prime.

It is equal to p_6590218 and since 115325437 and 6590218 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 115325399 and 115325408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115325407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57662718 + 57662719.

It is an arithmetic number, because the mean of its divisors is an integer number (57662719).

Almost surely, 2^115325437 is an apocalyptic number.

It is an amenable number.

115325437 is a deficient number, since it is larger than the sum of its proper divisors (1).

115325437 is an equidigital number, since it uses as much as digits as its factorization.

115325437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12600, while the sum is 31.

The square root of 115325437 is about 10738.9681534121. The cubic root of 115325437 is about 486.7527004860.

Adding to 115325437 its reverse (734523511), we get a palindrome (849848948).

The spelling of 115325437 in words is "one hundred fifteen million, three hundred twenty-five thousand, four hundred thirty-seven".