Base | Representation |
---|---|
bin | 10101011110110111… |
… | …01100100101101111 |
3 | 1002202202202122222212 |
4 | 22233123230211233 |
5 | 142110000123134 |
6 | 5144232401035 |
7 | 555542435612 |
oct | 125733544557 |
9 | 32682678885 |
10 | 11533207919 |
11 | 49892168a2 |
12 | 229a54617b |
13 | 111a5388ac |
14 | 7b5a2c179 |
15 | 4777b6bce |
hex | 2af6ec96f |
11533207919 has 2 divisors, whose sum is σ = 11533207920. Its totient is φ = 11533207918.
The previous prime is 11533207913. The next prime is 11533207921. The reversal of 11533207919 is 91970233511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11533207919 is a prime.
It is a super-2 number, since 2×115332079192 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 11533207921, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11533207913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5766603959 + 5766603960.
It is an arithmetic number, because the mean of its divisors is an integer number (5766603960).
Almost surely, 211533207919 is an apocalyptic number.
11533207919 is a deficient number, since it is larger than the sum of its proper divisors (1).
11533207919 is an equidigital number, since it uses as much as digits as its factorization.
11533207919 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51030, while the sum is 41.
The spelling of 11533207919 in words is "eleven billion, five hundred thirty-three million, two hundred seven thousand, nine hundred nineteen".
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