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11533302154981 is a prime number
BaseRepresentation
bin1010011111010100111001…
…1000001100011011100101
31111211120110122202010222101
42213311032120030123211
53002430200322424411
640310154215332101
72300152656540565
oct247651630143345
944746418663871
1011533302154981
113747278437342
121363293681031
1365877cac2079
142bc3015c0da5
1515001ac928c1
hexa7d4e60c6e5

11533302154981 has 2 divisors, whose sum is σ = 11533302154982. Its totient is φ = 11533302154980.

The previous prime is 11533302154973. The next prime is 11533302154987. The reversal of 11533302154981 is 18945120333511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8673790716900 + 2859511438081 = 2945130^2 + 1691009^2 .

It is a cyclic number.

It is not a de Polignac number, because 11533302154981 - 23 = 11533302154973 is a prime.

It is a super-2 number, since 2×115333021549812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11533302154987) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5766651077490 + 5766651077491.

It is an arithmetic number, because the mean of its divisors is an integer number (5766651077491).

Almost surely, 211533302154981 is an apocalyptic number.

It is an amenable number.

11533302154981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11533302154981 is an equidigital number, since it uses as much as digits as its factorization.

11533302154981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 388800, while the sum is 46.

The spelling of 11533302154981 in words is "eleven trillion, five hundred thirty-three billion, three hundred two million, one hundred fifty-four thousand, nine hundred eighty-one".