1153334053541 has 4 divisors (see below), whose sum is σ = 1156818446784. Its totient is φ = 1149849660300.

The previous prime is 1153334053507. The next prime is 1153334053549. The reversal of 1153334053541 is 1453504333511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1153334053541 - 2⁶ = 1153334053477 is a prime.

It is a super-3 number, since 3×1153334053541³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1153334053495 and 1153334053504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1153334053549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1742196125 + ... + 1742196786.

It is an arithmetic number, because the mean of its divisors is an integer number (289204611696).

Almost surely, 2^{1153334053541} is an apocalyptic number.

It is an amenable number.

1153334053541 is a deficient number, since it is larger than the sum of its proper divisors (3484393243).

1153334053541 is an equidigital number, since it uses as much as digits as its factorization.

1153334053541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3484393242.

The product of its (nonzero) digits is 162000, while the sum is 38.

The spelling of 1153334053541 in words is "one trillion, one hundred fifty-three billion, three hundred thirty-four million, fifty-three thousand, five hundred forty-one".