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11533354345 = 52306670869
BaseRepresentation
bin10101011110111000…
…10000010101101001
31002202210001002212001
422233130100111221
5142110014314340
65144235451001
7555543615532
oct125734202551
932683032761
1011533354345
114989306907
12229a5b6a61
13111a58a436
147b5a69689
154777e529a
hex2af710569

11533354345 has 4 divisors (see below), whose sum is σ = 13840025220. Its totient is φ = 9226683472.

The previous prime is 11533354321. The next prime is 11533354351. The reversal of 11533354345 is 54345333511.

11533354345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3937186009 + 7596168336 = 62747^2 + 87156^2 .

It is a cyclic number.

It is not a de Polignac number, because 11533354345 - 221 = 11531257193 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1153335430 + ... + 1153335439.

It is an arithmetic number, because the mean of its divisors is an integer number (3460006305).

Almost surely, 211533354345 is an apocalyptic number.

It is an amenable number.

11533354345 is a deficient number, since it is larger than the sum of its proper divisors (2306670875).

11533354345 is an equidigital number, since it uses as much as digits as its factorization.

11533354345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2306670874.

The product of its digits is 162000, while the sum is 37.

Adding to 11533354345 its reverse (54345333511), we get a palindrome (65878687856).

The spelling of 11533354345 in words is "eleven billion, five hundred thirty-three million, three hundred fifty-four thousand, three hundred forty-five".

Divisors: 1 5 2306670869 11533354345