Base | Representation |
---|---|
bin | 1010011111010111111101… |
… | …0011111001101000101000 |
3 | 1111211122120212112010122221 |
4 | 2213311333103321220220 |
5 | 3002433341004104000 |
6 | 40310411503323424 |
7 | 2300212215553315 |
oct | 247657723715050 |
9 | 44748525463587 |
10 | 11534123113000 |
11 | 3747659892244 |
12 | 13634825b0574 |
13 | 658880c02447 |
14 | 2bc37c643d0c |
15 | 150067da961a |
hex | a7d7f4f9a28 |
11534123113000 has 32 divisors (see below), whose sum is σ = 26989848086760. Its totient is φ = 4613649244800.
The previous prime is 11534123112923. The next prime is 11534123113021. The reversal of 11534123113000 is 31132143511.
It can be written as a sum of positive squares in 4 ways, for example, as 7566911643204 + 3967211469796 = 2750802^2 + 1991786^2 .
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5767060557 + ... + 5767062556.
Almost surely, 211534123113000 is an apocalyptic number.
11534123113000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11534123113000 is an abundant number, since it is smaller than the sum of its proper divisors (15455724973760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11534123113000 is a wasteful number, since it uses less digits than its factorization.
11534123113000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11534123134 (or 11534123120 counting only the distinct ones).
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 11534123113000 its reverse (31132143511), we get a palindrome (11565255256511).
The spelling of 11534123113000 in words is "eleven trillion, five hundred thirty-four billion, one hundred twenty-three million, one hundred thirteen thousand".
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