115342504013011 has 4 divisors (see below), whose sum is σ = 125828186196024. Its totient is φ = 104856821830000.

The previous prime is 115342504013003. The next prime is 115342504013071. The reversal of 115342504013011 is 110310405243511.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115342504013011 - 2³ = 115342504013003 is a prime.

It is a super-2 number, since 2×115342504013011² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (115342504013071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5242841091490 + ... + 5242841091511.

It is an arithmetic number, because the mean of its divisors is an integer number (31457046549006).

Almost surely, 2^{115342504013011} is an apocalyptic number.

115342504013011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

115342504013011 is a deficient number, since it is larger than the sum of its proper divisors (10485682183013).

115342504013011 is a wasteful number, since it uses less digits than its factorization.

115342504013011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10485682183012.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 115342504013011 its reverse (110310405243511), we get a palindrome (225652909256522).

The spelling of 115342504013011 in words is "one hundred fifteen trillion, three hundred forty-two billion, five hundred four million, thirteen thousand, eleven".