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11534320420015 = 52306864084003
BaseRepresentation
bin1010011111011000101100…
…0100100100010010101111
31111211200002121210101000011
42213312023010210102233
53002434242011420030
640310443232314051
72300220132623401
oct247661304442257
944750077711004
1011534320420015
1137477501a5998
1213635186a2927
136588b2a55a63
142bc39a924b71
1515007a380b2a
hexa7d8b1244af

11534320420015 has 4 divisors (see below), whose sum is σ = 13841184504024. Its totient is φ = 9227456336008.

The previous prime is 11534320420003. The next prime is 11534320420031. The reversal of 11534320420015 is 51002402343511.

11534320420015 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11534320420015 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1153432041997 + ... + 1153432042006.

It is an arithmetic number, because the mean of its divisors is an integer number (3460296126006).

Almost surely, 211534320420015 is an apocalyptic number.

11534320420015 is a deficient number, since it is larger than the sum of its proper divisors (2306864084009).

11534320420015 is an equidigital number, since it uses as much as digits as its factorization.

11534320420015 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2306864084008.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 11534320420015 its reverse (51002402343511), we get a palindrome (62536722763526).

The spelling of 11534320420015 in words is "eleven trillion, five hundred thirty-four billion, three hundred twenty million, four hundred twenty thousand, fifteen".

Divisors: 1 5 2306864084003 11534320420015