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115351034681 is a prime number
BaseRepresentation
bin110101101101101110…
…1010001101100111001
3102000202000022200222202
41223123131101230321
53342214331102211
6124554100555545
711222335421441
oct1533335215471
9360660280882
10115351034681
1144a13719723
121a4329b2bb5
13ab53cb490c
145823b41121
153001c8e53b
hex1adb751b39

115351034681 has 2 divisors, whose sum is σ = 115351034682. Its totient is φ = 115351034680.

The previous prime is 115351034639. The next prime is 115351034683. The reversal of 115351034681 is 186430153511.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111967867456 + 3383167225 = 334616^2 + 58165^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115351034681 is a prime.

It is a super-2 number, since 2×1153510346812 (a number of 23 digits) contains 22 as substring.

Together with 115351034683, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (115351034683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57675517340 + 57675517341.

It is an arithmetic number, because the mean of its divisors is an integer number (57675517341).

Almost surely, 2115351034681 is an apocalyptic number.

It is an amenable number.

115351034681 is a deficient number, since it is larger than the sum of its proper divisors (1).

115351034681 is an equidigital number, since it uses as much as digits as its factorization.

115351034681 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 38.

The spelling of 115351034681 in words is "one hundred fifteen billion, three hundred fifty-one million, thirty-four thousand, six hundred eighty-one".