Base | Representation |
---|---|
bin | 10000110010010011001… |
… | …001101001001111111100 |
3 | 11002021102210102012020210 |
4 | 100302103021221033330 |
5 | 122344402110424312 |
6 | 2241530401112420 |
7 | 146224205225520 |
oct | 20622311511774 |
9 | 4067383365223 |
10 | 1153520014332 |
11 | 405228a809a4 |
12 | 167687628710 |
13 | 84a12ba13ca |
14 | 3db8b4c5d80 |
15 | 200143a7e3c |
hex | 10c932693fc |
1153520014332 has 48 divisors (see below), whose sum is σ = 3084084928512. Its totient is φ = 328716623040.
The previous prime is 1153520014261. The next prime is 1153520014391. The reversal of 1153520014332 is 2334100253511.
It is a self number, because there is not a number n which added to its sum of digits gives 1153520014332.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17895219 + ... + 17959562.
It is an arithmetic number, because the mean of its divisors is an integer number (64251769344).
Almost surely, 21153520014332 is an apocalyptic number.
1153520014332 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1153520014332 is an abundant number, since it is smaller than the sum of its proper divisors (1930564914180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1153520014332 is a wasteful number, since it uses less digits than its factorization.
1153520014332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35855178 (or 35855176 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 1153520014332 its reverse (2334100253511), we get a palindrome (3487620267843).
The spelling of 1153520014332 in words is "one trillion, one hundred fifty-three billion, five hundred twenty million, fourteen thousand, three hundred thirty-two".
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