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1153530021341 is a prime number
BaseRepresentation
bin10000110010010011101…
…111110100010111011101
311002021110111020121021202
4100302103233310113131
5122344412141140331
62241531355405245
7146224356254465
oct20622357642735
94067414217252
101153530021341
11405233696355
1216768aa53825
1384a14c96209
143db8c96cba5
15200151d2ecb
hex10c93bf45dd

1153530021341 has 2 divisors, whose sum is σ = 1153530021342. Its totient is φ = 1153530021340.

The previous prime is 1153530021311. The next prime is 1153530021361. The reversal of 1153530021341 is 1431200353511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 670713498841 + 482816522500 = 818971^2 + 694850^2 .

It is an emirp because it is prime and its reverse (1431200353511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1153530021341 - 226 = 1153462912477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1153530021311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576765010670 + 576765010671.

It is an arithmetic number, because the mean of its divisors is an integer number (576765010671).

Almost surely, 21153530021341 is an apocalyptic number.

It is an amenable number.

1153530021341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1153530021341 is an equidigital number, since it uses as much as digits as its factorization.

1153530021341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 1153530021341 its reverse (1431200353511), we get a palindrome (2584730374852).

The spelling of 1153530021341 in words is "one trillion, one hundred fifty-three billion, five hundred thirty million, twenty-one thousand, three hundred forty-one".