Base | Representation |
---|---|
bin | 1010011111011101010000… |
… | …0101100001001001100111 |
3 | 1111211210020222211002221111 |
4 | 2213313110011201021213 |
5 | 3002444244110443210 |
6 | 40311204552125451 |
7 | 2300262366055306 |
oct | 247672405411147 |
9 | 44753228732844 |
10 | 11535545406055 |
11 | 3748219718050 |
12 | 13637ba996887 |
13 | 658a49787c78 |
14 | 2bc4754ba43d |
15 | 1500ecba488a |
hex | a7dd4161267 |
11535545406055 has 32 divisors (see below), whose sum is σ = 15631751692800. Its totient is φ = 8095037059200.
The previous prime is 11535545406023. The next prime is 11535545406071. The reversal of 11535545406055 is 55060454553511.
11535545406055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11535545406055 - 25 = 11535545406023 is a prime.
It is a super-2 number, since 2×115355454060552 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 203926 + ... + 4807564.
It is an arithmetic number, because the mean of its divisors is an integer number (488492240400).
Almost surely, 211535545406055 is an apocalyptic number.
11535545406055 is a deficient number, since it is larger than the sum of its proper divisors (4096206286745).
11535545406055 is a wasteful number, since it uses less digits than its factorization.
11535545406055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4605255.
The product of its (nonzero) digits is 4500000, while the sum is 49.
Adding to 11535545406055 its reverse (55060454553511), we get a palindrome (66595999959566).
The spelling of 11535545406055 in words is "eleven trillion, five hundred thirty-five billion, five hundred forty-five million, four hundred six thousand, fifty-five".
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