11535774500557 has 4 divisors (see below), whose sum is σ = 12214349471196. Its totient is φ = 10857199529920.

The previous prime is 11535774500521. The next prime is 11535774500599. The reversal of 11535774500557 is 75500547753511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10577188603081 + 958585897476 = 3252259^2 + 979074^2 .

It is a cyclic number.

It is not a de Polignac number, because 11535774500557 - 2²³ = 11535766111949 is a prime.

It is a super-2 number, since 2×11535774500557² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11535774500498 and 11535774500507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11535774500507) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 339287485294 + ... + 339287485327.

It is an arithmetic number, because the mean of its divisors is an integer number (3053587367799).

Almost surely, 2^{11535774500557} is an apocalyptic number.

11535774500557 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

It is an amenable number.

11535774500557 is a deficient number, since it is larger than the sum of its proper divisors (678574970639).

11535774500557 is an equidigital number, since it uses as much as digits as its factorization.

11535774500557 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 678574970638.

The product of its (nonzero) digits is 12862500, while the sum is 55.

The spelling of 11535774500557 in words is "eleven trillion, five hundred thirty-five billion, seven hundred seventy-four million, five hundred thousand, five hundred fifty-seven".