Base | Representation |
---|---|
bin | 110101101110010001… |
… | …1010011101101001010 |
3 | 102000210021212101211101 |
4 | 1223130203103231022 |
5 | 3342234031033340 |
6 | 124555554252014 |
7 | 11222650442236 |
oct | 1533443235512 |
9 | 360707771741 |
10 | 115369392970 |
11 | 44a23018567 |
12 | 1a438b8700a |
13 | ab57a41a00 |
14 | 582635d5c6 |
15 | 30036b8c9a |
hex | 1adc8d3b4a |
115369392970 has 96 divisors (see below), whose sum is σ = 232952338800. Its totient is φ = 41070661632.
The previous prime is 115369392911. The next prime is 115369392997. The reversal of 115369392970 is 79293963511.
It can be written as a sum of positive squares in 24 ways, for example, as 39898864009 + 75470528961 = 199747^2 + 274719^2 .
It is a super-3 number, since 3×1153693929703 (a number of 34 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 49449924 + ... + 49452256.
Almost surely, 2115369392970 is an apocalyptic number.
115369392970 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
115369392970 is an abundant number, since it is smaller than the sum of its proper divisors (117582945830).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115369392970 is a wasteful number, since it uses less digits than its factorization.
115369392970 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3404 (or 3391 counting only the distinct ones).
The product of its (nonzero) digits is 2755620, while the sum is 55.
The spelling of 115369392970 in words is "one hundred fifteen billion, three hundred sixty-nine million, three hundred ninety-two thousand, nine hundred seventy".
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