Base | Representation |
---|---|
bin | 1010011111101101111110… |
… | …1000001100011101111101 |
3 | 1111212012211210220222012010 |
4 | 2213323133220030131331 |
5 | 3003032442201404203 |
6 | 40313230214401433 |
7 | 2300511541435140 |
oct | 247733750143575 |
9 | 44765753828163 |
10 | 11540034013053 |
11 | 374a112396a07 |
12 | 1364652060279 |
13 | 6592b36a2b40 |
14 | 2bc77d69c057 |
15 | 1502b1c92303 |
hex | a7edfa0c77d |
11540034013053 has 32 divisors (see below), whose sum is σ = 18937695492352. Its totient is φ = 6086985408000.
The previous prime is 11540034013051. The next prime is 11540034013087. The reversal of 11540034013053 is 35031043004511.
It is not a de Polignac number, because 11540034013053 - 21 = 11540034013051 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11540034013053.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11540034013051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 35382543 + ... + 35707203.
It is an arithmetic number, because the mean of its divisors is an integer number (591802984136).
Almost surely, 211540034013053 is an apocalyptic number.
11540034013053 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11540034013053 is a deficient number, since it is larger than the sum of its proper divisors (7397661479299).
11540034013053 is a wasteful number, since it uses less digits than its factorization.
11540034013053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 454885.
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 11540034013053 its reverse (35031043004511), we get a palindrome (46571077017564).
The spelling of 11540034013053 in words is "eleven trillion, five hundred forty billion, thirty-four million, thirteen thousand, fifty-three".
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