115401414053 has 2 divisors, whose sum is σ = 115401414054. Its totient is φ = 115401414052.

The previous prime is 115401414043. The next prime is 115401414061. The reversal of 115401414053 is 350414104511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115302351844 + 99062209 = 339562^2 + 9953^2 .

It is a cyclic number.

It is not a de Polignac number, because 115401414053 - 2⁸ = 115401413797 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115401414043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57700707026 + 57700707027.

It is an arithmetic number, because the mean of its divisors is an integer number (57700707027).

Almost surely, 2^115401414053 is an apocalyptic number.

It is an amenable number.

115401414053 is a deficient number, since it is larger than the sum of its proper divisors (1).

115401414053 is an equidigital number, since it uses as much as digits as its factorization.

115401414053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 115401414053 its reverse (350414104511), we get a palindrome (465815518564).

The spelling of 115401414053 in words is "one hundred fifteen billion, four hundred one million, four hundred fourteen thousand, fifty-three".