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11540213231 = 21221543811
BaseRepresentation
bin10101011111101100…
…11010110111101111
31002210020221120110212
422233312122313233
5142113243310411
65145042453035
7555656123351
oct125766326757
932706846425
1011540213231
114992171008
1222a096417b
13111bb1c351
147b69330d1
154781ec68b
hex2afd9adef

11540213231 has 4 divisors (see below), whose sum is σ = 11540778264. Its totient is φ = 11539648200.

The previous prime is 11540213227. The next prime is 11540213257. The reversal of 11540213231 is 13231204511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13231204511 = 71890172073.

It is a cyclic number.

It is not a de Polignac number, because 11540213231 - 22 = 11540213227 is a prime.

It is a super-2 number, since 2×115402132312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11540213197 and 11540213206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11540213831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250685 + ... + 293126.

It is an arithmetic number, because the mean of its divisors is an integer number (2885194566).

Almost surely, 211540213231 is an apocalyptic number.

11540213231 is a deficient number, since it is larger than the sum of its proper divisors (565033).

11540213231 is an equidigital number, since it uses as much as digits as its factorization.

11540213231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 565032.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 11540213231 its reverse (13231204511), we get a palindrome (24771417742).

The spelling of 11540213231 in words is "eleven billion, five hundred forty million, two hundred thirteen thousand, two hundred thirty-one".

Divisors: 1 21221 543811 11540213231