Base | Representation |
---|---|
bin | 1101110000011… |
… | …10011011000001 |
3 | 22001011001101012 |
4 | 12320032123001 |
5 | 214020334213 |
6 | 15241250305 |
7 | 2600622146 |
oct | 670163301 |
9 | 261131335 |
10 | 115402433 |
11 | 5a161613 |
12 | 32793995 |
13 | 1aba7383 |
14 | 114803cd |
15 | a1e84a8 |
hex | 6e0e6c1 |
115402433 has 2 divisors, whose sum is σ = 115402434. Its totient is φ = 115402432.
The previous prime is 115402421. The next prime is 115402451. The reversal of 115402433 is 334204511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 68178049 + 47224384 = 8257^2 + 6872^2 .
It is a cyclic number.
It is not a de Polignac number, because 115402433 - 214 = 115386049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115402399 and 115402408.
It is not a weakly prime, because it can be changed into another prime (115402733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57701216 + 57701217.
It is an arithmetic number, because the mean of its divisors is an integer number (57701217).
Almost surely, 2115402433 is an apocalyptic number.
It is an amenable number.
115402433 is a deficient number, since it is larger than the sum of its proper divisors (1).
115402433 is an equidigital number, since it uses as much as digits as its factorization.
115402433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 23.
The square root of 115402433 is about 10742.5524434373. The cubic root of 115402433 is about 486.8610017546.
Adding to 115402433 its reverse (334204511), we get a palindrome (449606944).
The spelling of 115402433 in words is "one hundred fifteen million, four hundred two thousand, four hundred thirty-three".
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