115403943 has 4 divisors (see below), whose sum is σ = 153871928. Its totient is φ = 76935960.

The previous prime is 115403933. The next prime is 115403957. The reversal of 115403943 is 349304511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 349304511 = 3 ⋅116434837.

It is not a de Polignac number, because 115403943 - 2¹⁶ = 115338407 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 115403943.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115403923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19233988 + ... + 19233993.

It is an arithmetic number, because the mean of its divisors is an integer number (38467982).

Almost surely, 2^115403943 is an apocalyptic number.

115403943 is a deficient number, since it is larger than the sum of its proper divisors (38467985).

115403943 is an equidigital number, since it uses as much as digits as its factorization.

115403943 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38467984.

The product of its (nonzero) digits is 6480, while the sum is 30.

The square root of 115403943 is about 10742.6227244561. The cubic root of 115403943 is about 486.8631252133.

The spelling of 115403943 in words is "one hundred fifteen million, four hundred three thousand, nine hundred forty-three".