11541241153 has 4 divisors (see below), whose sum is σ = 12429028948. Its totient is φ = 10653453360.

The previous prime is 11541241147. The next prime is 11541241171. The reversal of 11541241153 is 35114214511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35114214511 = 593 ⋅59214527.

It can be written as a sum of positive squares in 2 ways, for example, as 1062238464 + 10479002689 = 32592^2 + 102367^2 .

It is a cyclic number.

It is not a de Polignac number, because 11541241153 - 2²⁵ = 11507686721 is a prime.

It is a super-3 number, since 3×11541241153³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11541241123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 443893878 + ... + 443893903.

It is an arithmetic number, because the mean of its divisors is an integer number (3107257237).

Almost surely, 2^11541241153 is an apocalyptic number.

11541241153 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11541241153 is a deficient number, since it is larger than the sum of its proper divisors (887787795).

11541241153 is an equidigital number, since it uses as much as digits as its factorization.

11541241153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 887787794.

The product of its digits is 2400, while the sum is 28.

Adding to 11541241153 its reverse (35114214511), we get a palindrome (46655455664).

The spelling of 11541241153 in words is "eleven billion, five hundred forty-one million, two hundred forty-one thousand, one hundred fifty-three".