Base | Representation |
---|---|
bin | 11010001111110001011101… |
… | …110010010000101101010111 |
3 | 120010201022001020000101020001 |
4 | 122033301131302100231113 |
5 | 110112224004303112043 |
6 | 1045301123555152131 |
7 | 33212524121025361 |
oct | 3217613562205527 |
9 | 503638036011201 |
10 | 115433114504023 |
11 | 338649aa891048 |
12 | 10b438645a5647 |
13 | 4c543b03a1824 |
14 | 2070dc77c5d31 |
15 | d52a30ab774d |
hex | 68fc5dc90b57 |
115433114504023 has 32 divisors (see below), whose sum is σ = 124970256967680. Its totient is φ = 106228271923200.
The previous prime is 115433114503991. The next prime is 115433114504063. The reversal of 115433114504023 is 320405411334511.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 115433114504023 - 25 = 115433114503991 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115433114504063) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 202871323 + ... + 203439523.
It is an arithmetic number, because the mean of its divisors is an integer number (3905320530240).
Almost surely, 2115433114504023 is an apocalyptic number.
115433114504023 is a deficient number, since it is larger than the sum of its proper divisors (9537142463657).
115433114504023 is a wasteful number, since it uses less digits than its factorization.
115433114504023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 569707.
The product of its (nonzero) digits is 86400, while the sum is 37.
Adding to 115433114504023 its reverse (320405411334511), we get a palindrome (435838525838534).
The spelling of 115433114504023 in words is "one hundred fifteen trillion, four hundred thirty-three billion, one hundred fourteen million, five hundred four thousand, twenty-three".
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