Base | Representation |
---|---|
bin | 110101110000001011… |
… | …0111010001001001001 |
3 | 102000221202000202010110 |
4 | 1223200112322021021 |
5 | 3342401403021101 |
6 | 125010155104533 |
7 | 11224354306356 |
oct | 1534026721111 |
9 | 360852022113 |
10 | 115433251401 |
11 | 44a56074326 |
12 | 1a456442149 |
13 | ab6803cc70 |
14 | 5830a2362d |
15 | 30090cecd6 |
hex | 1ae05ba249 |
115433251401 has 32 divisors (see below), whose sum is σ = 171267812352. Its totient is φ = 68675777280.
The previous prime is 115433251393. The next prime is 115433251411. The reversal of 115433251401 is 104152334511.
It is not a de Polignac number, because 115433251401 - 23 = 115433251393 is a prime.
It is not an unprimeable number, because it can be changed into a prime (115433251411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1177591 + ... + 1271843.
It is an arithmetic number, because the mean of its divisors is an integer number (5352119136).
Almost surely, 2115433251401 is an apocalyptic number.
It is an amenable number.
115433251401 is a deficient number, since it is larger than the sum of its proper divisors (55834560951).
115433251401 is a wasteful number, since it uses less digits than its factorization.
115433251401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95313.
The product of its (nonzero) digits is 7200, while the sum is 30.
Adding to 115433251401 its reverse (104152334511), we get a palindrome (219585585912).
The spelling of 115433251401 in words is "one hundred fifteen billion, four hundred thirty-three million, two hundred fifty-one thousand, four hundred one".
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