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11543325461 is a prime number
BaseRepresentation
bin10101100000000100…
…10010101100010101
31002210110210200122122
422300002102230111
5142120042403321
65145233305325
7556024435043
oct126002225425
932713720578
1011543325461
1149939a72a8
1222a1a05245
13111c66bac5
147b7103393
154786148ab
hex2b0092b15

11543325461 has 2 divisors, whose sum is σ = 11543325462. Its totient is φ = 11543325460.

The previous prime is 11543325427. The next prime is 11543325481. The reversal of 11543325461 is 16452334511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6566022961 + 4977302500 = 81031^2 + 70550^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11543325461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11543325401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5771662730 + 5771662731.

It is an arithmetic number, because the mean of its divisors is an integer number (5771662731).

Almost surely, 211543325461 is an apocalyptic number.

It is an amenable number.

11543325461 is a deficient number, since it is larger than the sum of its proper divisors (1).

11543325461 is an equidigital number, since it uses as much as digits as its factorization.

11543325461 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 43200, while the sum is 35.

Adding to 11543325461 its reverse (16452334511), we get a palindrome (27995659972).

The spelling of 11543325461 in words is "eleven billion, five hundred forty-three million, three hundred twenty-five thousand, four hundred sixty-one".