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115440161330213 is a prime number
BaseRepresentation
bin11010001111111000000001…
…110011110001010000100101
3120010201222020022212020110122
4122033320001303301100211
5110112332422300031323
61045304251125131325
733213163546043216
oct3217700163612045
9503658208766418
10115440161330213
1133867996608945
1210b450b0559b45
134c54c642c1375
14207149565140d
15d52ce4580ec8
hex68fe01cf1425

115440161330213 has 2 divisors, whose sum is σ = 115440161330214. Its totient is φ = 115440161330212.

The previous prime is 115440161330201. The next prime is 115440161330257. The reversal of 115440161330213 is 312033161044511.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110269803889249 + 5170357440964 = 10500943^2 + 2273842^2 .

It is a cyclic number.

It is not a de Polignac number, because 115440161330213 - 212 = 115440161326117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115440161332213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57720080665106 + 57720080665107.

It is an arithmetic number, because the mean of its divisors is an integer number (57720080665107).

Almost surely, 2115440161330213 is an apocalyptic number.

It is an amenable number.

115440161330213 is a deficient number, since it is larger than the sum of its proper divisors (1).

115440161330213 is an equidigital number, since it uses as much as digits as its factorization.

115440161330213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 115440161330213 in words is "one hundred fifteen trillion, four hundred forty billion, one hundred sixty-one million, three hundred thirty thousand, two hundred thirteen".