Base | Representation |
---|---|
bin | 10101100000001100… |
… | …00001101100101111 |
3 | 1002210112122102112210 |
4 | 22300012001230233 |
5 | 142120320220211 |
6 | 5145310301503 |
7 | 556035653142 |
oct | 126006015457 |
9 | 32715572483 |
10 | 11544304431 |
11 | 4994505870 |
12 | 22a21b7893 |
13 | 111c92258a |
14 | 7b72ba059 |
15 | 4787599a6 |
hex | 2b0181b2f |
11544304431 has 32 divisors (see below), whose sum is σ = 16891315200. Its totient is φ = 6955159680.
The previous prime is 11544304423. The next prime is 11544304433. The reversal of 11544304431 is 13440344511.
It is not a de Polignac number, because 11544304431 - 23 = 11544304423 is a prime.
It is a super-2 number, since 2×115443044312 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11544304433) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6916065 + ... + 6917733.
It is an arithmetic number, because the mean of its divisors is an integer number (527853600).
Almost surely, 211544304431 is an apocalyptic number.
11544304431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11544304431 is a deficient number, since it is larger than the sum of its proper divisors (5347010769).
11544304431 is a wasteful number, since it uses less digits than its factorization.
11544304431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2799.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 11544304431 its reverse (13440344511), we get a palindrome (24984648942).
The spelling of 11544304431 in words is "eleven billion, five hundred forty-four million, three hundred four thousand, four hundred thirty-one".
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