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115450102342 = 257725051171
BaseRepresentation
bin110101110000101011…
…1001100001001000110
3102000222220201212021101
41223201113030021012
53342420211233332
6125012000210314
711224650451441
oct1534127141106
9360886655241
10115450102342
1144a64633723
121a46000999a
13ab6b68cc33
145832d6c658
15300a80cae7
hex1ae15cc246

115450102342 has 4 divisors (see below), whose sum is σ = 173175153516. Its totient is φ = 57725051170.

The previous prime is 115450102307. The next prime is 115450102351. The reversal of 115450102342 is 243201054511.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1154501023422 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 115450102342.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28862525584 + ... + 28862525587.

It is an arithmetic number, because the mean of its divisors is an integer number (43293788379).

Almost surely, 2115450102342 is an apocalyptic number.

115450102342 is a deficient number, since it is larger than the sum of its proper divisors (57725051174).

115450102342 is an equidigital number, since it uses as much as digits as its factorization.

115450102342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57725051173.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 115450102342 its reverse (243201054511), we get a palindrome (358651156853).

The spelling of 115450102342 in words is "one hundred fifteen billion, four hundred fifty million, one hundred two thousand, three hundred forty-two".

Divisors: 1 2 57725051171 115450102342