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11545145445553 is a prime number
BaseRepresentation
bin1010100000000001000001…
…0010110000110010110001
31111212201001000222122101221
42220000100102300302301
53003123424213224203
640315433330225041
72301052316051536
oct250002022606261
944781030878357
1011545145445553
1137512a5693895
121365639a25181
13659919648b05
142bcb06488d8d
151504b08aaabd
hexa80104b0cb1

11545145445553 has 2 divisors, whose sum is σ = 11545145445554. Its totient is φ = 11545145445552.

The previous prime is 11545145445523. The next prime is 11545145445583. The reversal of 11545145445553 is 35554454154511.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (11545145445523) and next prime (11545145445583).

It can be written as a sum of positive squares in only one way, i.e., 10944531295504 + 600614150049 = 3308252^2 + 774993^2 .

It is a cyclic number.

It is not a de Polignac number, because 11545145445553 - 237 = 11407706492081 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11545145445553.

It is not a weakly prime, because it can be changed into another prime (11545145445503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5772572722776 + 5772572722777.

It is an arithmetic number, because the mean of its divisors is an integer number (5772572722777).

Almost surely, 211545145445553 is an apocalyptic number.

It is an amenable number.

11545145445553 is a deficient number, since it is larger than the sum of its proper divisors (1).

11545145445553 is an equidigital number, since it uses as much as digits as its factorization.

11545145445553 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12000000, while the sum is 52.

The spelling of 11545145445553 in words is "eleven trillion, five hundred forty-five billion, one hundred forty-five million, four hundred forty-five thousand, five hundred fifty-three".