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115454130551311 is a prime number
BaseRepresentation
bin11010010000000101000010…
…011100000111101000001111
3120010210022021212102012022211
4122100011002130013220033
5110113100024410120221
61045314521222051251
733214166661340306
oct3220050234075017
9503708255365284
10115454130551311
11338729048a4472
1210b4794a879b27
134c5637c414876
14207201c9d543d
15d53360b346e1
hex690142707a0f

115454130551311 has 2 divisors, whose sum is σ = 115454130551312. Its totient is φ = 115454130551310.

The previous prime is 115454130551303. The next prime is 115454130551351. The reversal of 115454130551311 is 113155031454511.

It is an a-pointer prime, because the next prime (115454130551351) can be obtained adding 115454130551311 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115454130551311 - 23 = 115454130551303 is a prime.

It is a super-2 number, since 2×1154541305513112 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115454130551351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57727065275655 + 57727065275656.

It is an arithmetic number, because the mean of its divisors is an integer number (57727065275656).

Almost surely, 2115454130551311 is an apocalyptic number.

115454130551311 is a deficient number, since it is larger than the sum of its proper divisors (1).

115454130551311 is an equidigital number, since it uses as much as digits as its factorization.

115454130551311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90000, while the sum is 40.

The spelling of 115454130551311 in words is "one hundred fifteen trillion, four hundred fifty-four billion, one hundred thirty million, five hundred fifty-one thousand, three hundred eleven".