1154640433 has 2 divisors, whose sum is σ = 1154640434. Its totient is φ = 1154640432.

The previous prime is 1154640407. The next prime is 1154640451. The reversal of 1154640433 is 3340464511.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1153825024 + 815409 = 33968^2 + 903^2 .

It is a cyclic number.

It is not a de Polignac number, because 1154640433 - 2²¹ = 1152543281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1154640395 and 1154640404.

It is not a weakly prime, because it can be changed into another prime (1154647433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 577320216 + 577320217.

It is an arithmetic number, because the mean of its divisors is an integer number (577320217).

Almost surely, 2^1154640433 is an apocalyptic number.

It is an amenable number.

1154640433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1154640433 is an equidigital number, since it uses as much as digits as its factorization.

1154640433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

The square root of 1154640433 is about 33980.0004855797. Note that the first 3 decimals coincide. The cubic root of 1154640433 is about 1049.0968599854.

The spelling of 1154640433 in words is "one billion, one hundred fifty-four million, six hundred forty thousand, four hundred thirty-three".