115512400431245 has 4 divisors (see below), whose sum is σ = 138614880517500. Its totient is φ = 92409920344992.

The previous prime is 115512400431229. The next prime is 115512400431299. The reversal of 115512400431245 is 542134004215511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 19905678250084 + 95606722181161 = 4461578^2 + 9777869^2 .

It is a cyclic number.

It is not a de Polignac number, because 115512400431245 - 2⁴ = 115512400431229 is a prime.

It is a super-2 number, since 2×115512400431245² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 115512400431199 and 115512400431208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11551240043120 + ... + 11551240043129.

It is an arithmetic number, because the mean of its divisors is an integer number (34653720129375).

Almost surely, 2^{115512400431245} is an apocalyptic number.

It is an amenable number.

115512400431245 is a deficient number, since it is larger than the sum of its proper divisors (23102480086255).

115512400431245 is an equidigital number, since it uses as much as digits as its factorization.

115512400431245 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23102480086254.

The product of its (nonzero) digits is 96000, while the sum is 38.

Adding to 115512400431245 its reverse (542134004215511), we get a palindrome (657646404646756).

The spelling of 115512400431245 in words is "one hundred fifteen trillion, five hundred twelve billion, four hundred million, four hundred thirty-one thousand, two hundred forty-five".