1155201253 has 4 divisors (see below), whose sum is σ = 1155375180. Its totient is φ = 1155027328.

The previous prime is 1155201251. The next prime is 1155201301. The reversal of 1155201253 is 3521025511.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3521025511 = 41 ⋅85878671.

It can be written as a sum of positive squares in 2 ways, for example, as 289782529 + 865418724 = 17023^2 + 29418^2 .

It is a cyclic number.

It is not a de Polignac number, because 1155201253 - 2¹ = 1155201251 is a prime.

It is a super-3 number, since 3×1155201253³ (a number of 28 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1155201251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76588 + ... + 90421.

It is an arithmetic number, because the mean of its divisors is an integer number (288843795).

Almost surely, 2^1155201253 is an apocalyptic number.

It is an amenable number.

1155201253 is a deficient number, since it is larger than the sum of its proper divisors (173927).

1155201253 is an equidigital number, since it uses as much as digits as its factorization.

1155201253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 173926.

The product of its (nonzero) digits is 1500, while the sum is 25.

The square root of 1155201253 is about 33988.2516908416. The cubic root of 1155201253 is about 1049.2666846493.

Adding to 1155201253 its reverse (3521025511), we get a palindrome (4676226764).

The spelling of 1155201253 in words is "one billion, one hundred fifty-five million, two hundred one thousand, two hundred fifty-three".