Base | Representation |
---|---|
bin | 10101100001001111… |
… | …00101101000001001 |
3 | 1002211011012102000110 |
4 | 22300213211220021 |
5 | 142130043233340 |
6 | 5150223024533 |
7 | 556203515061 |
oct | 126047455011 |
9 | 32734172013 |
10 | 11553102345 |
11 | 4999474874 |
12 | 22a513b149 |
13 | 11216b2c45 |
14 | 7b852a3a1 |
15 | 4793e6680 |
hex | 2b09e5a09 |
11553102345 has 8 divisors (see below), whose sum is σ = 18484963776. Its totient is φ = 6161654576.
The previous prime is 11553102343. The next prime is 11553102347. The reversal of 11553102345 is 54320135511.
It is an interprime number because it is at equal distance from previous prime (11553102343) and next prime (11553102347).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11553102345 - 21 = 11553102343 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11553102343) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 385103397 + ... + 385103426.
It is an arithmetic number, because the mean of its divisors is an integer number (2310620472).
Almost surely, 211553102345 is an apocalyptic number.
11553102345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11553102345 is a deficient number, since it is larger than the sum of its proper divisors (6931861431).
11553102345 is an equidigital number, since it uses as much as digits as its factorization.
11553102345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 770206831.
The product of its (nonzero) digits is 9000, while the sum is 30.
Adding to 11553102345 its reverse (54320135511), we get a palindrome (65873237856).
The spelling of 11553102345 in words is "eleven billion, five hundred fifty-three million, one hundred two thousand, three hundred forty-five".
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