115551131 has 2 divisors, whose sum is σ = 115551132. Its totient is φ = 115551130.

The previous prime is 115551101. The next prime is 115551133. The reversal of 115551131 is 131155511.

It is a strong prime.

It is an emirp because it is prime and its reverse (131155511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115551131 - 2¹⁴ = 115534747 is a prime.

It is a super-2 number, since 2×115551131² = 26704127750758322, which contains 22 as substring.

Together with 115551133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 115551097 and 115551106.

It is not a weakly prime, because it can be changed into another prime (115551133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57775565 + 57775566.

It is an arithmetic number, because the mean of its divisors is an integer number (57775566).

Almost surely, 2^115551131 is an apocalyptic number.

115551131 is a deficient number, since it is larger than the sum of its proper divisors (1).

115551131 is an equidigital number, since it uses as much as digits as its factorization.

115551131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 375, while the sum is 23.

The square root of 115551131 is about 10749.4711962961. The cubic root of 115551131 is about 487.0700215688.

The spelling of 115551131 in words is "one hundred fifteen million, five hundred fifty-one thousand, one hundred thirty-one".