Base | Representation |
---|---|
bin | 10101100001100000… |
… | …01010011000001111 |
3 | 1002211022102121021002 |
4 | 22300300022120033 |
5 | 142131132200111 |
6 | 5150343130515 |
7 | 556231566101 |
oct | 126060123017 |
9 | 32738377232 |
10 | 11555350031 |
11 | 499a76a565 |
12 | 22a5a43a3b |
13 | 1121cbc034 |
14 | 7b8953571 |
15 | 4796dc63b |
hex | 2b0c0a60f |
11555350031 has 2 divisors, whose sum is σ = 11555350032. Its totient is φ = 11555350030.
The previous prime is 11555349991. The next prime is 11555350033. The reversal of 11555350031 is 13005355511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11555350031 - 222 = 11551155727 is a prime.
It is a super-2 number, since 2×115553500312 (a number of 21 digits) contains 22 as substring.
Together with 11555350033, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 11555349976 and 11555350003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11555350033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5777675015 + 5777675016.
It is an arithmetic number, because the mean of its divisors is an integer number (5777675016).
Almost surely, 211555350031 is an apocalyptic number.
11555350031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11555350031 is an equidigital number, since it uses as much as digits as its factorization.
11555350031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5625, while the sum is 29.
The spelling of 11555350031 in words is "eleven billion, five hundred fifty-five million, three hundred fifty thousand, thirty-one".
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