Base | Representation |
---|---|
bin | 100010011101010… |
… | …0110101000000101 |
3 | 2222120121201102002 |
4 | 1010322212220011 |
5 | 4331442311003 |
6 | 310421355045 |
7 | 40436436056 |
oct | 10472465005 |
9 | 2876551362 |
10 | 1156213253 |
11 | 54371a148 |
12 | 283268a85 |
13 | 155703170 |
14 | ad7b272d |
15 | 6b78ba88 |
hex | 44ea6a05 |
1156213253 has 4 divisors (see below), whose sum is σ = 1245152748. Its totient is φ = 1067273760.
The previous prime is 1156213241. The next prime is 1156213271. The reversal of 1156213253 is 3523126511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 82864609 + 1073348644 = 9103^2 + 32762^2 .
It is a cyclic number.
It is not a de Polignac number, because 1156213253 - 210 = 1156212229 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1156213273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44469728 + ... + 44469753.
It is an arithmetic number, because the mean of its divisors is an integer number (311288187).
Almost surely, 21156213253 is an apocalyptic number.
1156213253 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1156213253 is a deficient number, since it is larger than the sum of its proper divisors (88939495).
1156213253 is an equidigital number, since it uses as much as digits as its factorization.
1156213253 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88939494.
The product of its digits is 5400, while the sum is 29.
The square root of 1156213253 is about 34003.1359289110. The cubic root of 1156213253 is about 1049.5729943239.
Adding to 1156213253 its reverse (3523126511), we get a palindrome (4679339764).
The spelling of 1156213253 in words is "one billion, one hundred fifty-six million, two hundred thirteen thousand, two hundred fifty-three".
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