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115647604873 is a prime number
BaseRepresentation
bin110101110110100100…
…0100110100010001001
3102001111200101000210221
41223231020212202021
53343321241323443
6125043333310041
711232566264533
oct1535510464211
9361450330727
10115647604873
1145056070259
121a4b6195321
13aba0581538
1458512a0853
15301cd21eed
hex1aed226889

115647604873 has 2 divisors, whose sum is σ = 115647604874. Its totient is φ = 115647604872.

The previous prime is 115647604867. The next prime is 115647604949. The reversal of 115647604873 is 378406746511.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103588709904 + 12058894969 = 321852^2 + 109813^2 .

It is a cyclic number.

It is not a de Polignac number, because 115647604873 - 25 = 115647604841 is a prime.

It is a super-2 number, since 2×1156476048732 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 115647604873.

It is not a weakly prime, because it can be changed into another prime (115647604273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57823802436 + 57823802437.

It is an arithmetic number, because the mean of its divisors is an integer number (57823802437).

Almost surely, 2115647604873 is an apocalyptic number.

It is an amenable number.

115647604873 is a deficient number, since it is larger than the sum of its proper divisors (1).

115647604873 is an equidigital number, since it uses as much as digits as its factorization.

115647604873 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3386880, while the sum is 52.

The spelling of 115647604873 in words is "one hundred fifteen billion, six hundred forty-seven million, six hundred four thousand, eight hundred seventy-three".