115734252557773 has 4 divisors (see below), whose sum is σ = 120766176582048. Its totient is φ = 110702328533500.

The previous prime is 115734252557731. The next prime is 115734252557827. The reversal of 115734252557773 is 377755252437511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115734252557773 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115734252554773) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2515962012103 + ... + 2515962012148.

It is an arithmetic number, because the mean of its divisors is an integer number (30191544145512).

Almost surely, 2^{115734252557773} is an apocalyptic number.

It is an amenable number.

115734252557773 is a deficient number, since it is larger than the sum of its proper divisors (5031924024275).

115734252557773 is an equidigital number, since it uses as much as digits as its factorization.

115734252557773 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5031924024274.

The product of its digits is 216090000, while the sum is 64.

The spelling of 115734252557773 in words is "one hundred fifteen trillion, seven hundred thirty-four billion, two hundred fifty-two million, five hundred fifty-seven thousand, seven hundred seventy-three".