11581680113 has 2 divisors, whose sum is σ = 11581680114. Its totient is φ = 11581680112.

The previous prime is 11581680101. The next prime is 11581680133. The reversal of 11581680113 is 31108618511.

It is a happy number.

11581680113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9942482944 + 1639197169 = 99712^2 + 40487^2 .

It is an emirp because it is prime and its reverse (31108618511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11581680113 is a prime.

It is not a weakly prime, because it can be changed into another prime (11581680133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5790840056 + 5790840057.

It is an arithmetic number, because the mean of its divisors is an integer number (5790840057).

Almost surely, 2^11581680113 is an apocalyptic number.

It is an amenable number.

11581680113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11581680113 is an equidigital number, since it uses as much as digits as its factorization.

11581680113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 35.

The spelling of 11581680113 in words is "eleven billion, five hundred eighty-one million, six hundred eighty thousand, one hundred thirteen".