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115850142047 is a prime number
BaseRepresentation
bin110101111100100110…
…1001110000101011111
3102002000210110222120202
41223321031032011133
53344230114021142
6125115410334115
711240605650113
oct1537115160537
9362023428522
10115850142047
114514a426452
121a551b8a33b
13ac03516613
145870143743
1530309cd032
hex1af934e15f

115850142047 has 2 divisors, whose sum is σ = 115850142048. Its totient is φ = 115850142046.

The previous prime is 115850142013. The next prime is 115850142049. The reversal of 115850142047 is 740241058511.

It is a strong prime.

It is an emirp because it is prime and its reverse (740241058511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115850142047 - 26 = 115850141983 is a prime.

Together with 115850142049, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115850142047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115850142049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57925071023 + 57925071024.

It is an arithmetic number, because the mean of its divisors is an integer number (57925071024).

Almost surely, 2115850142047 is an apocalyptic number.

115850142047 is a deficient number, since it is larger than the sum of its proper divisors (1).

115850142047 is an equidigital number, since it uses as much as digits as its factorization.

115850142047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 44800, while the sum is 38.

The spelling of 115850142047 in words is "one hundred fifteen billion, eight hundred fifty million, one hundred forty-two thousand, forty-seven".