Base | Representation |
---|---|
bin | 10101100111100011… |
… | …00000011011000001 |
3 | 1002221211210121202022 |
4 | 22303301200123001 |
5 | 142232121042423 |
6 | 5155353331225 |
7 | 560415443102 |
oct | 126361403301 |
9 | 32854717668 |
10 | 11606034113 |
11 | 4a16338233 |
12 | 22baa06b15 |
13 | 112c65690b |
14 | 7c15883a9 |
15 | 47dd9edc8 |
hex | 2b3c606c1 |
11606034113 has 4 divisors (see below), whose sum is σ = 12288742020. Its totient is φ = 10923326208.
The previous prime is 11606034109. The next prime is 11606034149. The reversal of 11606034113 is 31143060611.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31143060611 = 13 ⋅2395620047.
It can be written as a sum of positive squares in 2 ways, for example, as 5791666609 + 5814367504 = 76103^2 + 76252^2 .
It is a cyclic number.
It is not a de Polignac number, because 11606034113 - 22 = 11606034109 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11606034173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 341353928 + ... + 341353961.
It is an arithmetic number, because the mean of its divisors is an integer number (3072185505).
Almost surely, 211606034113 is an apocalyptic number.
It is an amenable number.
11606034113 is a deficient number, since it is larger than the sum of its proper divisors (682707907).
11606034113 is an equidigital number, since it uses as much as digits as its factorization.
11606034113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 682707906.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 11606034113 its reverse (31143060611), we get a palindrome (42749094724).
The spelling of 11606034113 in words is "eleven billion, six hundred six million, thirty-four thousand, one hundred thirteen".
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