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11613036305447 is a prime number
BaseRepresentation
bin1010100011111101111011…
…1001110101110000100111
31112010012021110121122222022
42220333132321311300213
53010231444243233242
640410542155053355
72306004602615633
oct250773671656047
945105243548868
1011613036305447
113778074274765
12137682644125b
13663148b25265
142c2106d15dc3
15152135c4b0d2
hexa8fdee75c27

11613036305447 has 2 divisors, whose sum is σ = 11613036305448. Its totient is φ = 11613036305446.

The previous prime is 11613036305419. The next prime is 11613036305461. The reversal of 11613036305447 is 74450363031611.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11613036305447 - 216 = 11613036239911 is a prime.

It is a super-2 number, since 2×116130363054472 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11613036305398 and 11613036305407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11613036305467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5806518152723 + 5806518152724.

It is an arithmetic number, because the mean of its divisors is an integer number (5806518152724).

Almost surely, 211613036305447 is an apocalyptic number.

11613036305447 is a deficient number, since it is larger than the sum of its proper divisors (1).

11613036305447 is an equidigital number, since it uses as much as digits as its factorization.

11613036305447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 44.

The spelling of 11613036305447 in words is "eleven trillion, six hundred thirteen billion, thirty-six million, three hundred five thousand, four hundred forty-seven".