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11613223024141 is a prime number
BaseRepresentation
bin1010100011111110101000…
…0010000111011000001101
31112010012202110221221212111
42220333222002013120031
53010232340043233031
640411012505104021
72306012330656204
oct250775202073015
945105673857774
1011613223024141
11377815a706232
121376878a88011
1366317870c2ab
142c2123a3c23b
151521473301b1
hexa8fea08760d

11613223024141 has 2 divisors, whose sum is σ = 11613223024142. Its totient is φ = 11613223024140.

The previous prime is 11613223024033. The next prime is 11613223024153. The reversal of 11613223024141 is 14142032231611.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9698528148516 + 1914694875625 = 3114246^2 + 1383725^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11613223024141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11613223024181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5806611512070 + 5806611512071.

It is an arithmetic number, because the mean of its divisors is an integer number (5806611512071).

Almost surely, 211613223024141 is an apocalyptic number.

It is an amenable number.

11613223024141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11613223024141 is an equidigital number, since it uses as much as digits as its factorization.

11613223024141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 11613223024141 its reverse (14142032231611), we get a palindrome (25755255255752).

The spelling of 11613223024141 in words is "eleven trillion, six hundred thirteen billion, two hundred twenty-three million, twenty-four thousand, one hundred forty-one".