Base | Representation |
---|---|
bin | 1010100011111111010011… |
… | …0000101110010110000111 |
3 | 1112010020020000122102021101 |
4 | 2220333310300232112013 |
5 | 3010233222132431120 |
6 | 40411042415000531 |
7 | 2306016644604430 |
oct | 250776460562607 |
9 | 45106200572241 |
10 | 11613403014535 |
11 | 3778242271723 |
12 | 1376909209147 |
13 | 6631a6aab99a |
14 | 2c213d8d2487 |
15 | 15215803590a |
hex | a8ff4c2e587 |
11613403014535 has 32 divisors (see below), whose sum is σ = 16787028954240. Its totient is φ = 7543800595968.
The previous prime is 11613403014523. The next prime is 11613403014547. The reversal of 11613403014535 is 53541030431611.
It is an interprime number because it is at equal distance from previous prime (11613403014523) and next prime (11613403014547).
It is not a de Polignac number, because 11613403014535 - 211 = 11613403012487 is a prime.
It is a super-2 number, since 2×116134030145352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11613403014494 and 11613403014503.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 107887492 + ... + 107995081.
It is an arithmetic number, because the mean of its divisors is an integer number (524594654820).
Almost surely, 211613403014535 is an apocalyptic number.
11613403014535 is a deficient number, since it is larger than the sum of its proper divisors (5173625939705).
11613403014535 is a wasteful number, since it uses less digits than its factorization.
11613403014535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 215882667.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 11613403014535 in words is "eleven trillion, six hundred thirteen billion, four hundred three million, fourteen thousand, five hundred thirty-five".
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