11614347391 has 2 divisors, whose sum is σ = 11614347392. Its totient is φ = 11614347390.

The previous prime is 11614347319. The next prime is 11614347401. The reversal of 11614347391 is 19374341611.

11614347391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (11614347319) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11614347391 - 2¹⁷ = 11614216319 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11614347491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5807173695 + 5807173696.

It is an arithmetic number, because the mean of its divisors is an integer number (5807173696).

Almost surely, 2^11614347391 is an apocalyptic number.

11614347391 is a deficient number, since it is larger than the sum of its proper divisors (1).

11614347391 is an equidigital number, since it uses as much as digits as its factorization.

11614347391 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54432, while the sum is 40.

The spelling of 11614347391 in words is "eleven billion, six hundred fourteen million, three hundred forty-seven thousand, three hundred ninety-one".