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11615406244133 is a prime number
BaseRepresentation
bin1010100100000110110000…
…1010011100000100100101
31112010102101122002000200012
42221001230022130010211
53010301322444303013
640412013255100005
72306120411020106
oct251015412340445
945112348060605
1011615406244133
11377908001477a
121377188071605
13663435b17043
142c228d98c3ad
15152223d351a8
hexa906c29c125

11615406244133 has 2 divisors, whose sum is σ = 11615406244134. Its totient is φ = 11615406244132.

The previous prime is 11615406244121. The next prime is 11615406244207. The reversal of 11615406244133 is 33144260451611.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9944896523809 + 1670509720324 = 3153553^2 + 1292482^2 .

It is a cyclic number.

It is not a de Polignac number, because 11615406244133 - 218 = 11615405981989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11615406244103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5807703122066 + 5807703122067.

It is an arithmetic number, because the mean of its divisors is an integer number (5807703122067).

Almost surely, 211615406244133 is an apocalyptic number.

It is an amenable number.

11615406244133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11615406244133 is an equidigital number, since it uses as much as digits as its factorization.

11615406244133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 207360, while the sum is 41.

Adding to 11615406244133 its reverse (33144260451611), we get a palindrome (44759666695744).

The spelling of 11615406244133 in words is "eleven trillion, six hundred fifteen billion, four hundred six million, two hundred forty-four thousand, one hundred thirty-three".