Base | Representation |
---|---|
bin | 10101101010000011… |
… | …10001001001010111 |
3 | 1010000022101120020101 |
4 | 22311001301021113 |
5 | 142303012333020 |
6 | 5201424314531 |
7 | 561062333215 |
oct | 126501611127 |
9 | 33008346211 |
10 | 11627074135 |
11 | 4a271a8986 |
12 | 2305a72a47 |
13 | 1133b12531 |
14 | 7c42a3cb5 |
15 | 480b5900a |
hex | 2b5071257 |
11627074135 has 4 divisors (see below), whose sum is σ = 13952488968. Its totient is φ = 9301659304.
The previous prime is 11627074091. The next prime is 11627074183. The reversal of 11627074135 is 53147072611.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53147072611 = 11731 ⋅4530481.
It is a cyclic number.
It is not a de Polignac number, because 11627074135 - 213 = 11627065943 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11627074094 and 11627074103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1162707409 + ... + 1162707418.
It is an arithmetic number, because the mean of its divisors is an integer number (3488122242).
Almost surely, 211627074135 is an apocalyptic number.
11627074135 is a deficient number, since it is larger than the sum of its proper divisors (2325414833).
11627074135 is an equidigital number, since it uses as much as digits as its factorization.
11627074135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2325414832.
The product of its (nonzero) digits is 35280, while the sum is 37.
The spelling of 11627074135 in words is "eleven billion, six hundred twenty-seven million, seventy-four thousand, one hundred thirty-five".
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