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116306435237 is a prime number
BaseRepresentation
bin110110001010001100…
…1110101110010100101
3102010012121002002011112
41230110121311302211
53401143421411422
6125232550314405
711255116250006
oct1542431656245
9363177062145
10116306435237
1145363a50263
121a65a958a05
13ac76c078a5
1458b499d1ad
15305aab0ee2
hex1b14675ca5

116306435237 has 2 divisors, whose sum is σ = 116306435238. Its totient is φ = 116306435236.

The previous prime is 116306435233. The next prime is 116306435239. The reversal of 116306435237 is 732534603611.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107842619236 + 8463816001 = 328394^2 + 91999^2 .

It is a cyclic number.

It is not a de Polignac number, because 116306435237 - 22 = 116306435233 is a prime.

Together with 116306435239, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 116306435194 and 116306435203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (116306435233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58153217618 + 58153217619.

It is an arithmetic number, because the mean of its divisors is an integer number (58153217619).

Almost surely, 2116306435237 is an apocalyptic number.

It is an amenable number.

116306435237 is a deficient number, since it is larger than the sum of its proper divisors (1).

116306435237 is an equidigital number, since it uses as much as digits as its factorization.

116306435237 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 272160, while the sum is 41.

The spelling of 116306435237 in words is "one hundred sixteen billion, three hundred six million, four hundred thirty-five thousand, two hundred thirty-seven".