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1163124287471 is a prime number
BaseRepresentation
bin10000111011001111100…
…111000010011111101111
311010012020010112211011202
4100323033213002133233
5123024034304144341
62250155410040115
7150014206214036
oct20731747023757
94105203484152
101163124287471
11409307379513
12169507b7903b
13858b38b5273
144041cc7771d
15203c764879b
hex10ecf9c27ef

1163124287471 has 2 divisors, whose sum is σ = 1163124287472. Its totient is φ = 1163124287470.

The previous prime is 1163124287449. The next prime is 1163124287473. The reversal of 1163124287471 is 1747824213611.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1163124287471 is a prime.

It is a super-3 number, since 3×11631242874713 (a number of 37 digits) contains 333 as substring.

Together with 1163124287473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1163124287473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 581562143735 + 581562143736.

It is an arithmetic number, because the mean of its divisors is an integer number (581562143736).

Almost surely, 21163124287471 is an apocalyptic number.

1163124287471 is a deficient number, since it is larger than the sum of its proper divisors (1).

1163124287471 is an equidigital number, since it uses as much as digits as its factorization.

1163124287471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 451584, while the sum is 47.

The spelling of 1163124287471 in words is "one trillion, one hundred sixty-three billion, one hundred twenty-four million, two hundred eighty-seven thousand, four hundred seventy-one".